Use a formula with a difference of twice on both sides. It would be sad if the boss of that large company was paid more than twice as much. by Nada 20231024

Hello. This is Nada from Seito Medical School. There are various combinations of calculations for A=B and C=D. It's a restaurant that has so many combinations that it's hard to order.

Adding A=B and C=D gives A+C=B+D. If we subtract A=B and C=D, we get AC=BD. When multiplied, AC=BD or AD=BC. When divided, A/C=B/D.

If (A/B)=(C/D) is A=1, B=3, C=2, D=6, (1/3)=(2/6) is also correct, but C is twice as much as A, and D is twice as much as B. In other words, (2/2) x (1/3) = (2/6).

In this state, if (A/B) = (C/D), we can derive A=C between the numerators and B=D between the denominators. However, please note that the correct answer is Ax2=C, which means 1×2=2. Regarding B=D, Bx2=D and 3×2=6.

However, here we purposely use an equation with a difference of two times on both sides. It would be sad if the boss of that large company was paid more than twice as much. It would have been twice as good...

First, add both sides of A=C and B=D. A+B=C+D. This will look like this: A+B=1+3=4, C+D=2+6=8. Therefore, the state where there is a difference of 2 times on both sides will be preserved. Of course, even if AB=CD, 1×3=2×6 and 3=12, so the difference is 4 times. Multiplying the 2x difference twice will give you a 4x difference.

So far, things are good, but from here on out, we are currently researching. Sample below.

(A+B) x D=(C+D) x B

(1+3) x 6 = (2+6) x 3

The above was a sample. Have a nice day tomorrow. See you soon.